Regex, Removing Recurring Characters But Keeping At Least One

I'm using this html = html.replace(/([^0-9]).*?\1/ , ''); but it's not quite doing what I'm trying to do. I want to replace the doubles within a string, but still keep at least o

Solution 1:

THink you mean this,

str.replace(/(.)\1+/g, '$1')

or

str.replace(/([^0-9])\1+/g, '$1')