Remove First Occurrence Of Comma In A String

I am looking for a way to remove the first occurrence of a comma in a string, for example 'some text1, some tex2, some text3' should return instead: 'some text1 some text2, some t

Solution 1:

This will do it:

if (str.match(/,.*,/)) { // Check if there are 2 commas
    str = str.replace(',', ''); // Remove the first one
}

When you use the replace method with a string rather than an RE, it just replaces the first match.

Solution 2:

String.prototype.replace replaces only the first occurence of the match:

"some text1, some tex2, some text3".replace(',', '')
// => "some text1 some tex2, some text3"

Global replacement occurs only when you specify the regular expression with g flag.

---

var str = ",.,.";
if (str.match(/,/g).length > 1) // if there's more than one comma
    str = str.replace(',', '');

Solution 3:

A simple one liner will do it:

text = text.replace(/^(?=(?:[^,]*,){2})([^,]*),/, '$1');

Here is how it works:

regex = re.compile(r"""
    ^                # Anchor to start of line|string.
    (?=              # Look ahead to make sure
      (?:[^,]*,){2}  # There are at least 2 commas.
    )                # End lookahead assertion.
    ([^,]*)          # $1: Zero or more non-commas.
    ,                # First comma is to be stripped.
    """, re.VERBOSE)

Solution 4:

you could also use a lookahead like so ^(.*?),(?=.*,) and replace w/ $1Demo

Solution 5:

a way with split:

var txt = 'some text1, some text2, some text3';

var arr = txt.split(',', 3);

if (arr.length == 3)
    txt = arr[0] + arr[1] + ',' + arr[2];

or shorter:

if ((arr = txt.split(',', 3)).length == 3)
    txt = arr[0] + arr[1] + ',' + arr[2];

If there are less than 3 elements in the array (less than 2 commas) the string stay unchanged. The split method use the limit parameter (set to 3), as soon as the limit of 3 elements is reached, the split method stops.

or with replace:

txt = txt.replace(/,(?=[^,]*,)/, '');