Javascript - Sort Array Of Objects, By A Property Based On A Special Order

I have an array of objects with multiple properties. Given the following array: var people = [ {name: 'allen', age: 33, color:'green'}, {name: 'jon', age: 23, color:'bl

Solution 1:

Here is your comparator

varsortOrder= {green:0, yellow:1, brown:2, pink:3, grey:4, blonde:5};people.sort(function(p1,p2) {
   returnsortOrder[p1.color] -sortOrder[p2.color];
});

Solution 2:

I suggest to use a default value as well for sorting, depending where the non listed color should be sorted.

In this case the properties of the sort order object have to start with a value above zero.

colorOrder= { green:1, yellow:2, brown:3, pink:4, grey:5, blonde:6 };people.sort(function(a,b) {
    return(colorOrder[a.color] ||0)-(colorOrder[b.color] ||0);
});

Solution 3:

Use Andrey method, add just one param in your object :

varsortOrder= {green:0, yellow:1, brown:2, pink:3, grey:4, blonde:5};people.sort(function(p1,p2) {
   returnsortOrder[p1.color] -sortOrder[p2.color];
});

Or if you really can't use that, create your sort function :

var people =
[
    {name: "allen", age: 33, color:"green"},
    {name: "jon", age: 23, color:"blonde"},
    {name: "silver", age: 54, color:"yellow"},
    {name: "james", age: 52, color:"grey"},
    {name: "flint", age: 25, color:"pink"},
    {name: "beilly", age: 31, color:"blonde"},
    {name: "bwones", age: 47, color:"grey"},
    {name: "sas", age: 35, color:"green"},
    {name: "jackson", age: 234, color:"yellow"},
    {name: "leonsardo", age: 12, color:"brown"},
    {name: "dicaeprio", age: 73, color:"pink"},
    {name: "sylvfester", age: 35, color:"blonde"},
    {name: "alleen2", age: 33, color:"green"},
    {name: "jofn2", age: 23, color:"blonde"},
    {name: "sdilver2", age: 54, color:"yellow"},
    {name: "jamaes2", age: 52, color:"grey"}
];

var order = ['green','yellow','brown','pink','grey','blonde'];
functionmySort(array)
{
    varlist = [];
    functiongetElem(array,id)
    {
        for(var i in array) if(array[i].color == id) list.push(array[i])
    }

    for(var i in order) getElem(array,order[i]);
    returnlist;
}

mySort(people);

Solution 4:

I guess the proper way of doing this job is by a hash and sort but without using sort the following code might as well turn out to be pretty efficient.

var people = [
      {name: "allen", age: 33, color:"green"},
      {name: "jon", age: 23, color:"blonde"},
      {name: "silver", age: 54, color:"yellow"},
      {name: "james", age: 52, color:"grey"},
      {name: "flint", age: 25, color:"pink"},
      {name: "beilly", age: 31, color:"blonde"},
      {name: "bwones", age: 47, color:"grey"},
      {name: "sas", age: 35, color:"green"},
      {name: "jackson", age: 234, color:"yellow"},
      {name: "leonsardo", age: 12, color:"brown"},
      {name: "dicaeprio", age: 73, color:"pink"},
      {name: "sylvfester", age: 35, color:"blonde"},
      {name: "alleen2", age: 33, color:"green"},
      {name: "jofn2", age: 23, color:"blonde"},
      {name: "sdilver2", age: 54, color:"yellow"},
      {name: "jamaes2", age: 52, color:"grey"}
    ],
    arrays = [green, yellow, brown, pink, grey, blonde] = [[],[],[],[],[],[]],
    result = [];
    Object.keys(people).forEach(k =>this[people[k].color].push(people[k]));
    result = arrays.reduce((p,c) => p.concat(c));
console.log(result);

For an improved performance you might replace the last line with

result = arrays.reduce((p,c) => (Array.prototype.push.apply(p,c),p));