Filter Javascript Objects With Another Array
I have Javascript array of objets like this var posts = [ {area: 'NY', name: 'Bla', ads: true}, {area: 'DF', name: 'SFS', ads: false}, {area: 'TT', name: 'SDSD', ads: true}, {a
Solution 1:
There is only need single Array#filter
method and the second condition should be indexOf(post.area) > -1;
since index starts from 0
.
var posts = [
{area: 'NY', name: 'Bla', ads: true},
{area: 'DF', name: 'SFS', ads: false},
{area: 'TT', name: 'SDSD', ads: true},
{area: 'SD', name: 'Engine', ads: false},
{area: 'NSK', name: 'Toyota', ads: false},
];
var filter = ['NY', 'SD'];
functionfiltered(p, f) {
return p
.filter(function(v) {
return v.ads && f.indexOf(v.area) > -1;
})
}
console.log(filtered(posts, filter));
Solution 2:
This is a typical use case for Array.prototype.filter()
and Array.prototype.some()
combo.
var posts = [
{area: 'NY', name: 'Bla', ads: true},
{area: 'DF', name: 'SFS', ads: false},
{area: 'TT', name: 'SDSD', ads: true},
{area: 'SD', name: 'Engine', ads: false},
{area: 'NSK', name: 'Toyota', ads: false},
],
filter = ['NY', 'SD'];
result = posts.filter(o => filter.some(f => o.ads && f === o.area));
console.log(result);
// or with filter & includes combo
result = posts.filter(o => o.ads && filter.includes(o.area));
console.log(result);
Solution 3:
You could use a more generic solution with constraints for filtering.
functionfilter(array, constraints) {
return array.filter(function(a) {
returnObject.keys(constraints).every(function(k) {
returntypeof constraints[k] === 'function' ? constraints[k](a[k]) : a[k] === constraints[k] ;
});
});
}
var posts = [{ area: 'NY', name: 'Bla', ads: true }, { rea: 'DF', name: 'SFS', ads: false }, { area: 'TT', name: 'SDSD', ads: true }, { rea: 'SD', name: 'Engine', ads: false }, { area: 'NSK', ame: 'Toyota', ads: false }],
result = filter(posts, {
ads: true,
area: function (v) { return ['NY', 'SD'].indexOf(v) !== -1; }
});
console.log(result);
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